Question 8 of Question 8 (2 points) What values of x satisfy the equation 2x2 + 3x – 10 = 2x + 5 a x =3/2 or x=-5 x=-5/2 or x=2 x=10 or x=-1/2 X=-3 or x=5/2 Next Page Back

Question

asked Feb 25, 2020 137k views

1 Answer

Aneef · Answer 1 · 2020-02-28T16:21:20+0000

Answer:

$x=-3\ or\ (5)/(2)$

Explanation:

Given:

Given equation is.

Find values of x?

Solution.

2x^(2) +3x-10=2x+5

2x^(2) +3x-10-2x-5=0

2x^(2) +x-15=0

Find the roots of the equation.

compare the above equation with

Therefore,

$x=\frac{-b\pm\sqrt{(b)^(2)-4ac}}{2a}$

Put a,b and c value in above equation.

$x=\frac{-1\pm\sqrt{(1)^(2)-4(2)(-15)}}{2(2)}$

$x=(-1\pm√(1-8(-15)))/(4)$

$x=(-1\pm√(1+120))/(4)$

$x=(-1\pm√(121))/(4)$

$x=\frac{-1\pm\sqrt{(11)^(2)}}{4}$

$x=(-1\pm 11)/(4)$

For positive sign

x=(-1+ 11)/(4)

x=(10)/(4)

x=(5)/(2)

For negative sign

x=(-1- 11)/(4)

x=(-12)/(4)

x=-3

$x=-3\ or\ (5)/(2)$

Therefore, the value of
$x=-3\ or\ (5)/(2)$ satisfy the given equation.