Trigonometry Question pls help

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Elegance asked Jul 8, 2023

213,762 views

34 votes

Trigonometry Question pls help

Mathematics
high-school

Elegance asked Jul 8, 2023

by Elegance

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1 Answer

8 votes

Answer:

Hello,

Explanation:

In the triangle ABG, using law of sin

$(sin(121^o))/(7) =(sin(41^o))/(AG) =(sin(18^o))/(BG) \\\\AG=(sin(41^o)*7)/(sin(121^o)) =5.358(km)\\\\BG=(sin(18^o)*7)/(sin(121^o)) =2.526(km)\\\\CG=5+BG=7.526(km)\\\\GD=CG*sin(31^o)=3.875(km)\\\\AD=AG+GD=9.233(km)\\\\CD=CG*cos(31^o)=6.451(km)\\\\AC=√(AD^2+CD^2) =11.263(km)\\$