The number of adult tickets sold is 165 and number of students tickets sold were 35
Solution:
Let "a" be the number of adult tickets sold
Let "s" be the number of student tickets sold
Cost of 1 adult ticket = $ 50.00
Student tickets are 50% less than adult tickets
Cost of 1 student ticket = Cost of 1 adult ticket - 50 % of Cost of 1 adult ticket
![\rightarrow 50.00 - 50 \% \text{ of } 50.00\\\\\rightarrow 50 - (50)/(100) * 50\\\\\rightarrow 50 - 25 = 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ah3dpb9jxrevwztahgfuksekea0mr4mqt8.png)
Thus Cost of 1 student ticket = $ 25
Given that a concert venue can hold 200 people
So we get,
number of adult tickets sold + number of student tickets sold = 200
a + s = 200 ----- eqn 1
The venue was sold out and made a revenue of $9125 for one event
So we can frame a equation as:
number of adult tickets sold x Cost of 1 adult ticket + number of student tickets sold x Cost of 1 student ticket = $ 9125
![a * 50.00 + s * 25 = 9125](https://img.qammunity.org/2020/formulas/mathematics/middle-school/52gd4em0b6t177m436d7ufweprabfiu8ts.png)
50a + 25s = 9125 ---- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "a" and "s"
From eqn 1,
a = 200 - s --- eqn 3
Substitute eqn 3 in eqn 2
50(200 - s) + 25s = 9125
10000 - 50s + 25s = 9125
-25s = 9125 - 10000
-25s = -875
s = 35
Substitute s = 35 in eqn 3
a = 200 - 35
a = 165
Thus the number of adult tickets sold is 165 and number of students tickets sold were 35