Question

Which of the following is correct about the equilibrium constant K if ΔG < 0?K is zeroK is less than 1K is equal to 1K is greater than 1

Answer 1

Answer : The correct option is, K is more than 1.

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

`\Delta G^o=-RT* \ln K`

where,

`\Delta G^o` = standard Gibbs free energy

R = gas constant

T = temperature

K = equilibrium constant

From the above relation we conclude that,

When K > 1 then the value of
`\Delta G^o` is negative.

When K < 1 then the value of
`\Delta G^o` is positive.

When K = 1 then the value of
`\Delta G^o` is zero.

When K = 0 then the value of
`\Delta G^o` is undefined.

As per question, if the value of ΔG < 0 that means negative value then value of equilibrium constant will be more than 1 that means K > 1.

Hence, the correct option is, K is more than 1.