Question

If 4.71 l of nitrogen gas and 24.96 l of hydrogen gas were allowed to react, how many liters of ammonia gas could form? assume all gases are at the same temperature and pressure.

Answer 1

To find the liters of ammonia gas that can form, convert the given volumes to moles, determine the limiting reactant, use the mole ratio, and convert back to liters. The answer is 3.16 L.

Step-by-step explanation:

To find the number of liters of ammonia gas that can form, we first need to determine the limiting reactant. The balanced chemical equation for the reaction is:

3H2(g) + N2(g) → 2NH3(g)

From the equation, we can see that 3 moles of hydrogen gas react with 1 mole of nitrogen gas to produce 2 moles of ammonia gas. Using the given volumes, we can convert them to moles:

4.71 L of nitrogen gas × (1 mol/24.96 L) = 0.189 mol

24.96 L of hydrogen gas × (1 mol/24.96 L) = 0.999 mol

Since nitrogen is the limiting reactant with 0.189 mol and the mole ratio is 3:2 (hydrogen gas to ammonia gas), we can calculate the moles of ammonia that can form:

0.189 mol of nitrogen gas × (2 mol NH3/3 mol N2) = 0.126 mol

Finally, we can convert the moles of ammonia to liters:

0.126 mol of ammonia gas × (24.96 L/0.999 mol) = 3.16