Question

A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground after t seconds is given by s(t)=112t-16t^2 At what time, in seconds, does the projectile achieve its maximum height?

Answer 1

3.48 seconds

Step-by-step explanation:

At maximum height Vf=0 m/s

Vf= Vi - g*t

⇒g*t= Vi

⇒t= Vi/g

⇒t= 112/32.17 sec

⇒ t= 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.