Question

a solution is produced that contains 2.00 moles of sucrose dissolved in 1.00 L of water as the solvent. What is the MOLALITY of the solution

Answer 1

`\boxed{\text{2.00 mol/L}}`

Step-by-step explanation:

`\begin{array}{rcl}b& = &\frac{\text{moles of solute}}{\text{kilograms of solvent}}\\& = & \frac{\text{2.00 mol}}{\text{1.00 kg}}\\\\& = &\textbf{2.00 mol/kg}\\\end{array}\\\text{The molal concentration of the solution is $\boxed{\textbf{2.00 mol/kg}}$}`