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The perimeter of a rectangle is 54 meter. The difference of the length and the width is 11 meters. Find the demensions of the rectangle. Can you please just show the equation thanks.

User Luke Wenke
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1 Answer

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Final answer:

To find the dimensions of the rectangle, set up a system of equations using the given information. Solve the system of equations using the substitution method. The dimensions of the rectangle are 19 meters by 8 meters.

Step-by-step explanation:

To find the dimensions of the rectangle, we'll start by assigning variables. Let L represent the length and W represent the width. Given that the difference between the length and width is 11 meters, we can set up the equation L - W = 11.

Additionally, we know that the perimeter of a rectangle is calculated as P = 2L + 2W. Since the perimeter is given as 54 meters, we can write the equation as 2L + 2W = 54.

1. Perimeter equation:

Perimeter = 2l + 2w = 54 meters

2. Difference equation:

l - w = 11 meters

Solving for l and w:

From equation 2, we can express l in terms of w: l = w + 11

Substitute this expression for l in equation 1:

2(w + 11) + 2w = 54

2w + 22 + 2w = 54

4w + 22 = 54

4w = 32

w = 8

Since l = w + 11, then:

l = 8 + 11 = 19

Therefore, the dimensions of the rectangle are 19 meters by 8 meters.

User Ben Rhouma Zied
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