Answer:
![S_ {12} = 192](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uaoa4tq5uxje52zcpqmw4h2hs3spcqgfos.png)
Explanation:
The nth term of the given arithmetic sequence is
![U_n = 3 + 2n](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xargnm0tnq6gs5hz6iaqsrk500a07pzlm8.png)
The first term of this series is:
![U_1 = 3 + 2(1) = 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1oefm1gelhos4d5vominxe3m89nmvaa5yp.png)
The last term of this series is when
![n = 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kbbzk0lsmbioh3gdd115ykowbzj9t9g0xe.png)
![U_ {12}= 3 + 2(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69vgth9y2zsx9gtday4fm5msp2txg182bz.png)
![U_ {12}= 3 + 24 = 27](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r4j1i99ct75qzrsiijcyd4j0ebjg5fef1k.png)
The sum of the first n terms of an arithmetic series when the first an last term is known is given by:
![S_n = (n)/(2)(a + l)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lc44243eoe9vwwmwj1d3qtkv05z9z4odxs.png)
Where a=5 is the first term and l=27 is the last term.
![S_ {12} = (12)/(2)(5 + 27)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/666qe1fyhzdy177b5y49cy1wr7lnby6k1s.png)
![S_ {12} =6(32) =19 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sdow779l2lm34q7rtosfi232sssqop23so.png)