Question

A normal human heart, beating about once per second, creates a maximum 4.00 mV potential across 0.400 m of a person's chest, producing a 1.00 Hz electromagnetic wave. What is the maximum electric field strength produced? maximum electric field strength: V / m What is the corresponding maximum magnetic field strength in the electromagnetic wave? maximum magnetic field strength: T What is the wavelength of the electromagnetic wave? wavelength:

Answer 1

The maximum electric field strength created by the heart is 0.01333 V/m, the corresponding maximum magnetic field strength in the electromagnetic wave is 4.44×10−6 T, and the wavelength of the electromagnetic wave is 3.00×10¸ m.

Step-by-step explanation:

When the human heart beats normally, it creates a maximum 4.00-mV potential across 0.300 m of a person's chest, which leads to the generation of a 1.00-Hz electromagnetic wave.

(a) Maximum Electric Field Strength:

The maximum electric field strength (E) can be calculated by taking the potential difference (V) and dividing it by the distance (d). Therefore, E = V/d = 4.00 mV / 0.300 m = 13.33 mV/m, which is equivalent to 0.01333 V/m.

(b) Corresponding Maximum Magnetic Field Strength:

Using the relationship between electric field (E) and magnetic field (B) in an electromagnetic wave, which is given by B = E/c, where c is the speed of light in vacuum (approximately 3.00×108 m/s). Thus, the maximum magnetic field strength is B = 0.01333 V/m / 3.00×108 m/s = 4.44×10−6 T.

(c) Wavelength of the Electromagnetic Wave:

The relationship between the speed of light (c), frequency (f), and wavelength (λ) of an electromagnetic wave is given by c = fλ. For a wave with a frequency of 1.00 Hz, the wavelength would be λ = c/f = 3.00×108 m/s / 1.00 Hz = 3.00×108 m.

Answer 2

To solve this problem it is necessary to apply the concepts related to the electric field as a function of voltage and distance, the magnetic field as a function of the speed of light and the electric field and finally the wavelength whose definition is based on the speed of light and frequency.

PART A) The maximum electric field strength produced is,

`E_(max) = (V_(max))/(d)`

`E_(max) = (4mV)/(0.4m)`

`E_(max) = \frac{4*10{-3}V}{0.4m}`

`E_(max) = 0.01V/m`

Therefore the maximum electric field strnegth produced is 0.01V/m

PART B) The maximum magnetic field strength in the electromagnetic wave is

`B_(max) = \frac{E_max}}{c}`

`B_(max) = (0.01V/m)/(3*10^8m/s)`

`B_(max) = 3.33*10^(-11)T`

Therefore the corresponding maximum magnetic field strengthintheelectromagnetic wave is
`3.33*10^(-11)T`

PART C) Wavelength of electromagnetic wave is,

`\lambda f = c`

`\lambda = (c)/(f)`

`\lambda = (3*10^8m/s)/(1Hz)`

`\lambda = 3*10^8m`

Therefore the wavelength of the electromagnetic wave
`3*10^8m`