Question

Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x.

show your work

Answer 1

`x=14`

Explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

`32=3x-10`

solve for x

`3x=32+10`

`3x=42`

`x=14`