Question

Answer to 4(x-3)+5x-^2 for x=2

Answer 1

Given expression
`4(x-3)+5x^(\bf -2)` for x=2 is

`4(x-3)+5x^(\bf -2)=-(\bf 11)/(\bf 4)`

Explanation:

Given expression is
`4(x-3)+5x^(-2)` for x=2

Let f(x) be the given expression

`f(x)=4(x-3)+5x^(-2)`

now to find f(x) for x=2

ie., put x=2 in f(x) we get

`4(x-3)+5x^(-2)=4(2-3)+5(2)^(-2)`

`4(x-3)+5x^(-2)=4(-1)+5(2)^(-2)`

`4(x-3)+5x^(-2)=-4+5* (1)/(2)^}2}`

`4(x-3)+5x^(-2)=-4+5* (1)/(4)`

`4(x-3)+5x^(-2)=-4+ (5)/(4)`

`4(x-3)+5x^(-2)= (-16+5)/(4)`

`4(x-3)+5x^(-2)= (-11)/(4)`

`4(x-3)+5x^(-2)=-(11)/(4)`

Therefore the given expression
`4(x-3)+5x^(-2)` for x=2 is

`4(x-3)+5x^(-2)=-(11)/(4)`