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A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.130 M AuNO 3 solution at 25 °C. The gold wire is connected to the positive end of a potentiometer, and the S.C.E. is connected to the negative end of the potentiometer. What is the half‑reaction that occurs at the Au electrode? Include physical states.

User Paquita
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Answer:

The half reaction occurring at this electrode will be given as:


Au^++e^-\rightarrow Au

Step-by-step explanation:

In electrochemical cell reduction occurs at anode.

But the gold wire is connected to the positive terminal of the battery which means that gold wire will act as a cathode nad reduction will take place

The half reaction occurring at this electrode will be given as:


Au^++e^-\rightarrow Au

User Murmansk
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