Question

Which statement best justifies the use of a high-speed cache in a CPU?

A.
It decreases the time it takes to decode instructions stored in the instruction pipeline.
B. It provides additional storage space for when the main memory runs out of free space.
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C.
It increases the number of instructions understood by the CPU.
D. It reduces the time required for memory read-write operations because it is part of the CPU.
E. It increases the time the CPU takes to execute instructions in one cycle.
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Answer 1

The use of a high-speed cache in a CPU can be justified as it reduces the time required for memory read-write operations by storing frequently accessed instructions and data close to the CPU, resulting in faster execution times.

Step-by-step explanation:

The use of a high-speed cache in a CPU can be justified by the fact that it reduces the time required for memory read-write operations because it is part of the CPU. The cache is a small, fast memory that stores frequently accessed instructions and data. By keeping frequently used information close to the CPU, it avoids the need to retrieve data from slower main memory, which results in faster execution times.

For example, when a program runs, the CPU first checks the cache for the required data or instructions. If the cache contains the requested data, the CPU can access it quickly. However, if the data is not in the cache, the CPU has to retrieve it from slower memory, which adds latency to the operation. By having a high-speed cache, the CPU can minimize the time spent waiting for data from main memory, improving overall performance.

Therefore, statement D is the best justification for the use of a high-speed cache in a CPU.

Answer 2

Cache memory is a high-speed memory that stores the instructions and data that have been frequently accessed. It decreases the time it takes to decode the instructions stored in the instruction pipeline.

A. It decreases the time it takes to decode instructions stored in the instruction pipeline.

Step-by-step explanation:

Whenever an instruction is invoked or some data is accessed, the CPU looks for it in the cache memory before accessing the main memory.

If the content is found in the cache memory, it accessed from there and then and hence the access time and decode time is reduced as there were no main memory lockups.