Using the wavelength expressions, such as the distance between two peaks of a wave, that of the frequency as a function of the speed and the wavelength, such as the period inversely proportional to the frequency we have to for the first question
the wavelength is the distance between the two ridges that is
![\lambda = 0.8m](https://img.qammunity.org/2020/formulas/physics/college/kb4w7in8qf1284cbbllnmhvy9u3etzlf07.png)
For the second question the frequency is determined as the rate of change of the velocity versus the wavelength, that is
![f = (v)/(\lambda)](https://img.qammunity.org/2020/formulas/physics/college/ezivdofqy9e2s0w93ntstmep2f3h7odaa6.png)
![f = (2.2)/(0.8)](https://img.qammunity.org/2020/formulas/physics/college/qyseszpdah2wg6lu4p6setwikte3c83t7b.png)
![f= 2.75Hz \approx 2.8Hz](https://img.qammunity.org/2020/formulas/physics/college/wf6n4asle4zws5yoidf2laekm6sg2timg5.png)
For the third question the period is inversely proportional to the frequency, therefore
![T = (1)/(f)](https://img.qammunity.org/2020/formulas/physics/college/wqpy9s9ewddptrdu601cp7m9jiqo73sa9k.png)
![T = (1)/(2.8)](https://img.qammunity.org/2020/formulas/physics/college/m3onhv1qiyzkibqnh8cu38u5dqw5lkj46q.png)
![T = 0.36s](https://img.qammunity.org/2020/formulas/physics/college/ru73dw1651lj1rzlgyw1bn48posu9e4cpd.png)