Question

Electronics and inhabitants of the International Space Station generate a significant amount of thermal energy that the station must get rid of. The only way that the station can exhaust thermal energy is by radiation, which it does by using thin, 1.8-m-by-3.6-m panels that have a working temperature of about 6C. How much power is radiated from each panel? Assume that the panels are in the shade so that the absorbed radiation will be negligible. Assume that the emissivity of the panel is 1.0.

Answer 1

4462.0927 W

Step-by-step explanation:

`\epsilon` = Emissivity of the panel = 1

`\sigma` = Stefan-Boltzmann constant =
`5.67* 10^(-8)\ W/m^2K^4`

T = Temperature = (273.15+6)

Area of the panel is given by

`A=2* 1.8* 3.6\\\Rightarrow A=12.96\ m^2`

The power radiated is given by

`P=\epsilon \sigma AT^4\\\Rightarrow P=1* 5.67* 10^(-8)* 12.96* (273.15+6)^4\\\Rightarrow P=4462.0927\ W`

The power radiated from each panel is 4462.0927 W