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The line above goes through points (-4,0) and (0,3). What is the equation of the line?

User Argus
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1 Answer

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The equation of line going through points (-4, 0) and (0, 3) is
y = (3)/(4)x + 3

Solution:

Given that line above goes through points (-4,0) and (0,3)

To find: equation of line

The equation of line passing through two points
(x_1 , y_1) and
(x_2, y_2) is given as:


y - y_1 = m(x - x_1)

Where "m" is the slope of line

The slope of line is given as:


m=(y_(2)-y_(1))/(x_(2)-x_(1))

Here for the given points (-4, 0) and (0, 3) we have:


x_1 = -4 ; y_1 = 0 ; x_2 = 0 ; y_2 = 3

Substituting the given values in slope formula,


m=(3-0)/(0-(-4))=(3)/(4)

Thus slope of line
m = (3)/(4)

Now substitute "m" into equation of line

Thus the required equation of line is:


y - y_1 = m(x - x_1)\\\\y - 0 = (3)/(4)(x - (-4))\\\\y = (3)/(4)(x + 4)\\\\y = (3)/(4)x + 3

Thus the required equation of line is found

User Ronny Vdb
by
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