Question

Aspirin (C9H8O4) may be synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3).

The balanced equation is C7H6O3 + C4H6O3 C9H8O4 + C2H4O2 When 2.0 g of salicylic acid is mixed with excess acetic anhydride, 1.7 g of aspirin is collected.

What is the percent yield for this reaction?

Answer 1

65.18% is the percent yield for this reaction.

Step-by-step explanation:

`C_7H_6O_3 + C_4H_6O_3\rightarrow C_9H_8O_4 + C_2H_4O_2`

Moles of salicyclic acid =
`(2.0 g)/(138 g/mol)=0.01449 mol`

According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .

Then 0.01449 mole of salicylic acid will give :

`(1)/(1)* 0.01449 mol=0.01449 mol` of asprin

Mass of 0.01449 moles of aspirin :

= 0.01449 mol × 180 g/mol = 2.6082 g

Theoretical yield of aspirin = 2.6082 g

Experimental yield of aspirin = 1.7 g

The percent yield for this reaction:

`\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100`

`=(1.7 g)/(2.6082 g)* 100=65.18\%`

65.18% is the percent yield for this reaction.