194k views
2 votes
Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) A) CCl4< CHCl3< NaNO3 B) CH3OH < CH4< LiF C) CH4< NaNO3< CHCl3 D) LiF < NaNO3< CHCl3 E) CH3OH < Cl2< CHCl3

User Fadia
by
8.2k points

1 Answer

3 votes

Answer:

A) CCl4< CHCl3< NaNO3

Step-by-step explanation:

answer is A

CCl4 is non polar and consequently has a very low solubility in water

CHCl3 is polar and soluble in water via London dispersion and dipole-dipole interaction forces.

NaNO3 is an ionic compound and more soluble in water (ion-dipole interactions)

Note: A) CCl4< CHCl3< NaNO3

User LaoR
by
8.3k points