Question

Which oxide of vanadium contains the greatest mass percent of the metal?VO2V2O3VOV2O5

Answer 1

Answer : The oxide of vanadium contains the greatest mass percent of the metal is,
`VO`

Explanation: Given,

Molar mass of vanadium = 50.9 g/mol

Now we have to calculate the mass percent of metal in the following compounds.

For
`VO_2` compound :

`\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO_2}* 100`

Molar mass of
`VO_2` = 82.9 g/mole

Now put all the given values in this formula, we get:

`\text{Mass percent of vanadium}=(50.9)/(82.9)* 100=61.4\%`

Therefore, the mass percent of vanadium metal is 61.4 %

For
`V_2O_3` compound :

`\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_3}* 100`

Molar mass of
`V_2O_3` = 149.8 g/mole

Now put all the given values in this formula, we get:

`\text{Mass percent of vanadium}=(50.9)/(149.8)* 100=33.9\%`

Therefore, the mass percent of vanadium metal is 33.9 %

For
`VO` compound :

`\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO}* 100`

Molar mass of
`VO` = 66.9 g/mole

Now put all the given values in this formula, we get:

`\text{Mass percent of vanadium}=(50.9)/(66.9)* 100=76.1\%`

Therefore, the mass percent of vanadium metal is 76.1 %

For
`V_2O_5` compound :

`\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_5}* 100`

Molar mass of
`V_2O_5` = 181.8 g/mole

Now put all the given values in this formula, we get:

`\text{Mass percent of vanadium}=(50.9)/(181.8)* 100=27.9\%`

Therefore, the mass percent of vanadium metal is 27.9 %

Hence, the oxide of vanadium contains the greatest mass percent of the metal is,
`VO`