Which oxide of vanadium contains the greatest mass percent of the metal?VO2V2O3VOV2O5

Question

asked Feb 21, 2020 80.5k views

1 Answer

Arusekk · Answer 1 · 2020-02-26T20:01:35+0000

Answer : The oxide of vanadium contains the greatest mass percent of the metal is,

Explanation: Given,

Molar mass of vanadium = 50.9 g/mol

Now we have to calculate the mass percent of metal in the following compounds.

For
compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO_2}* 100$

Molar mass of
VO_2 = 82.9 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=(50.9)/(82.9)* 100=61.4\%$

Therefore, the mass percent of vanadium metal is 61.4 %

For
compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_3}* 100$

Molar mass of
V_2O_3 = 149.8 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=(50.9)/(149.8)* 100=33.9\%$

Therefore, the mass percent of vanadium metal is 33.9 %

For
compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO}* 100$

Molar mass of
= 66.9 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=(50.9)/(66.9)* 100=76.1\%$

Therefore, the mass percent of vanadium metal is 76.1 %

For
compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_5}* 100$

Molar mass of
V_2O_5 = 181.8 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=(50.9)/(181.8)* 100=27.9\%$

Therefore, the mass percent of vanadium metal is 27.9 %

Hence, the oxide of vanadium contains the greatest mass percent of the metal is,