Answer:
8(x2 + 2x) = –3
8(x2 + 2x + 1) = –3 + 8
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Explanation:
Solving Quadratic Equations
Sometimes it's preferred to solve quadratic equations without the use of the known quadratic formula solver. One of the most-used methods consists of completing squares and solving for x.
We have the equation
![\displaystyle 8x^2+16x+3=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/733vmb2aqta3ghlo7hdptn4pcwpjho7itg.png)
We separate variables from constants
![\displaystyle 8x^2+16x=-3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/42hjd2l1wj7x6o6pdbd7macl7gqlk8fxvi.png)
Taking the common factor 8
![\displaystyle 8(x^2+2x)=-3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xsh87gdx6umw2eldf92g0c5v6g3lcr1lqr.png)
Completing squares in the brackets and balancing the equation in the right side
![\displaystyle 8(x^2+2x+1)=-3+8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7u0nfp3bsaumowdn3ec6zosa2fvbmhdxiq.png)
Factoring the perfect square
![\displaystyle 8(x+1)^2=5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1npssr4yniouc4h1am30yfio0z5d8ojca2.png)
Isolating x
![\displaystyle (x+1)^2=(5)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oiixn0i0y5a49uewkh6i5kv0dd98jv92qp.png)
![\displaystyle (x+1)=\pm \sqrt{(5)/(8)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ou8qh6blw1d7grjl9k8g2ronbhw7pg6mzz.png)
![\displaystyle x=-1\pm \sqrt{(5)/(8)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/35qjy3n151phze0vpy64l73c8uzm5ze2dc.png)
We can clearly see the steps used to solve the quadratic equation are (in order and written like in the question)
8(x2 + 2x) = –3
8(x2 + 2x + 1) = –3 + 8
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot