Answer:
0.3847 m/s
Step-by-step explanation:
= Intensity =
![(P)/(A)=(P)/(\pi r^2)](https://img.qammunity.org/2020/formulas/physics/college/gfxwqdxi71nvzdu8l7on04sgxhdn8bavjs.png)
d = Diameter = 20 cm
r = Radius =
![(d)/(2)=(20)/(2)=10\ cm](https://img.qammunity.org/2020/formulas/physics/college/g41tol2czc7f2ib0yqqm5r0n15jm46bcmo.png)
c = Speed of light =
![3* 10^8\ m/s](https://img.qammunity.org/2020/formulas/physics/high-school/ks86dmym7sxdf8u3g31nulpxe5c16w96hm.png)
s = Distance = 100 m
P = Power = 22 MW
Pressure due to the laser is given by
![P_r=(I)/(c)\\\Rightarrow P_r=(P)/(Ac)\\\Rightarrow P_r=(P)/(\pi r^2c)\\\Rightarrow P_r=(22* 10^(6))/(\pi 0.1^2* 3* 10^8)\\\Rightarrow P_r=2.33427\ N/m^2](https://img.qammunity.org/2020/formulas/physics/college/ombqrmrb7sw77i5ey9eiskctljghdx4qvy.png)
Force is given by
![F=P_rA\\\Rightarrow F=2.33427* \pi 0.1^2\\\Rightarrow F=0.07333\ N](https://img.qammunity.org/2020/formulas/physics/college/duaifbkjco2kn04bf6fyfhweh5tpbosflx.png)
Acceleration is given by
![a=(F)/(m)\\\Rightarrow a=(0.07333)/(99)\\\Rightarrow a=0.00074\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/umlbxqw3era8swe9uaqlt5izn68zwsk1fv.png)
Speed of the block would be
![v=√(2as)\\\Rightarrow v=√(2* 0.00074* 100)\\\Rightarrow v=0.3847\ m/s](https://img.qammunity.org/2020/formulas/physics/college/x0p3sywfolwinoo77wxvdayz9jwsuhu127.png)
The speed of the block is 0.3847 m/s