Answer:
program arraysminfinder;
procedure minreplace();
var
no: array [1..10] of integer; (*no is an array of integers, 10 in all *)
a: integer= 0;
i: integer= 0;
c: integer= 0;
k: integer=0;
N: integer=0;
begin
(* We need to first initialize the array no with 0 values *)
for a := 1 to 10 do
no[a]:=0;
c:=no[1];
for a := 1 to 10 do
begin
if (no[i]<c) then
begin
c:=no[i];
k:=i;
end
else
begin
i:=i+1;
end
end;
writeln('Enter the new number:');
read(N);
no[k]:=N;
for a := 1 to 10 do
begin
writeln('The array elements are:',no[a]);
end;
end;
begin
end.
Step-by-step explanation:
The program is as above. I have used a function, a for loop, an array of integers, and the if then else ladder for getting the desired output as mentioned in the program. If in case you want procedure for input and output, create a procedure like:
procedure replacenum():integer;
Begin
writeln("Enter the new number:" N);
no[k]:=N;
for a := 1 to 10 do
writeln("The array elements are:"no[a]);
end.
Similarly you can make a procedure for input.