If 100g of water loses 3000 j of energy, what is the temperature change ?

asked Dec 9, 2020 169k views

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4 votes

Answer:

∆T= -7.14°K

Step-by-step explanation:

Q=-3000J

m(H₂O)=0.1kg

C(H₂O)=4200J/kg•K

∆T=Q/C•m=

= -3000/4200•0.1= -7.14°K

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