Question

X2 + 4y2 = 36
The length of the minor axis is:

Answer 1

`length\ of \ minor\ axis = 6`

Explanation:

Given:

The given equation is.

`x^(2) +4y^(2) =36` -------------(1)

We write standard equation of an ellipse

`(x^(2))/(a^(2))+(y^(2) )/(b^(2) ) = 1`-------(2)

So equation 1 divided by 36 for standard form of an equation

`(x^(2))/(36)+(4y^(2) )/(36) = (36)/(36)`

`(x^(2))/(36)+(y^(2) )/(9) = 1`

So we compare equation 1 and equation 2.

we get
`a^(2) =36` and
`b^(2) =9`

so
`a =6` and
`b =3`

The length of the minor axis is
`2* b`

Here
`b=3`.

`length\ of \ minor\ axis = 2* 3`

`length\ of \ minor\ axis = 6`

Therefore the length of the minor axis is 6