18.6k views
2 votes
Solve triangle ABC if A = 50°, a = 10, and b = 20. If no triangle exists, explain why.

User Shauneba
by
7.2k points

2 Answers

4 votes

Answer:

No triangle exists

Explanation:

Angle B=? ------- a/sin(A)= b/sin (B) ------- substitute the given values ------- 10/sin(50º)=20/sin(B) ------- sin(B)=20(sin(50º))/10 ------- sin(B)=1.532

But the max value of sines is 1, so that means that no triangle exists.

User Hilmi
by
6.2k points
3 votes

Answer:

No triangle exist

Explanation:

step 1

Find the measure of angle B

Applying the law of sines


(a)/(sin(A))=(b)/(sin(B))

substitute the given values


(10)/(sin(50^o))=(20)/(sin(B))


sin(B)=20(sin(50^o))/10


sin(B)=1.532

Remember that

The maximum value of the sine is 1

therefore

No triangle exist

User Georgiann
by
6.3k points
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