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This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the percent increase in the enrollment? Which operation will you use in your first step?

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The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

Solution:

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

The percent increase is given as:


\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} * 100

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,


\begin{aligned}&\text { percentage increase }=(1272-1200)/(1200) * 100\\\\&\text { percentage increase }=(72)/(1200) * 100=6\end{aligned}

Thus percent increase is 6 %

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