Question

A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it

conveyor belt?
40 J
80 3
160 J
1,600 )

Answer 1

Kinetic energy of the box=80J

Explanation:

mass of the box=40 Kg

velocity of box= 2 m/s

Kinetic energy= 1/2 mV²

KE= 1/2 (40)(2)²

KE=80J

Thus kinetic energy of the box=80 J

Answer 2

K.E = 80 j

Step-by-step explanation:

Given data:

Mass of box = 40 Kg

Velocity = 2 m/s

K.E = ?

Solution:

K.E = 1/2 m.v²

K.E = 1/2 (40 Kg) (2 m/s)²

K.E = 1/2 (40 Kg) (4m²/s²}

K.E = 1/2 (160 Kg. m²/s²)

K.E = 80 Kg. m²/s²

Kg. m²/s² = j

K.E = 80 j