Question

In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?

Answer 1

Answer:
`a=1016.66 m/s^(2)`

Step-by-step explanation:

Acceleration
`a` is expressed in the following formula:

`a=(V_(f)-V_(o))/(t)`

Where:

`V_(f)=610 m/s` is the final velocity of the projectile

`V_(o)=0 m/s` is the initial velocity of the projectile

`t=0.6 s` is the time

Solving:

`a=(610 m/s-0 m/s)/(0.6 s)`

`a=1016.66 m/s^(2)` This is the acceleration of the projectile