Question

A force of 92.0N is exerted straight up on a small troll that weighs 73.5N. Find the acceleration of the troll.

Answer 1

23

Step-by-step explanation:

Answer 2

Answer:
`12.26 m/s^(2)`

Step-by-step explanation:

We have the following data:

`F=92 N` is the force exerted on the troll

`W=73.5 N` is the weight of the troll

Now, the weight is expressed as:

`W=m.g` (1)

Where
`m` is the mass of the troll and
`g=9.8 m/s^(2)` is the acceleration due gravity

Isolating
`m`:

`m=(W)/(g)` (2)

`m=(73.5 N)/(9.8 m/s^(2))` (3)

`m=7.5 kg` (4) This is the mass of th troll

On the other hand, the exerted force is given by:

`F=m.a` (5)

Where
`a` is the acceleration:

`a=(F)/(m)` (6)

`a=(92 N)/(7.5 kg)` (7)

Finally:

`a=12.26 m/s^(2)` This is the acceleration of the troll