Question

How do you completely factor 4k^2+14k+12?
please help me with the steps!

Answer 1

4k^2+14k+12 =(4k+6)(k+2)= 2(2k+3)(k+2)

Step-by-step explanation:

`4k^2+14k+12`

`4k^2+8k+6k+12`

4k(k+2) + 6(k+2)

(4k+6)(k+2)

2(2k+3)(k+2)is solution set