Question

Write the equation of the line that passes through the points (−6,1) and (−2,4).

Answer 1

The equation of the line is 3 x - 4 y + 22 = 0.

Explanation:

Here the given points are (-6, 1) & (-2, 4)

Equation of a line whose points are given such that

(
`x_(1), y_(1)`) & (
`x_(2), y_(2)` )-

y -
`y_(1)` =
`(y_(2) - y_(1) )/(x_(2) - x_(1) )` ( x -
`x_(1)` )

i.e. y - 1 =
`(4-1)/(-2 - (-6))` ( x- (-6))

y - 1 =
`(4-1)/(-2 + 6)` ( x + 6 )

y - 1 =
`(3)/(4)` ( x + 6 )

4 ( y - 1 ) = 3 ( x + 6)

4 y - 4 = 3 x + 18

3 x - 4 y + 22 = 0

Hence the equation of the required line whose passes trough the points ( -6, 1) & ( -2, 4) is 3 x - 4 y + 22 = 0.