Question

3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

Answer 1

9, 11, 13

Explanation:

Let n represent the smallest of the integers. Then n+4 is the largest of them. The given total is ...

n + 4(n+4) = 61

5n +16 = 61

5n = 45 . . . . . . subtract 16

n = 9 . . . . . . . . divide by 5

The smallest of the integers is 9, so the other two are 11 and 13.