Question

Does anyone know this? Please help.

Answer 1

`3^(11)`

Step-by-step explanation:

It is given in the question that:

`6x-2y=11`

Dividing both hand sides by 2, we get:

`3x-y=5.5`

We have to find the value of
`(9^(3x) )/(9^(y) )`.

From laws of exponents we know:

`(a^(m) )/(a^(n))=a^(m-n)`

So we can write :

`(9^(3x) )/(9^(y) )=9^(3x-y)`

`=9^(5.5)=3^(11)`

Answer 2

Answer:option C is the correct answer

Explanation:

The given equation is

6x - 2y = 11

Let us make x the subject of the formula. The first step is to add 2y to both the left hand side and the right hand side of the equation. It becomes

6x - 2y + 2y = 11 + 2y

6x = 11 + 2y

Dividing both the left hand side and the right hand side of the equation by 6. It becomes

6x/6 = (11 + 2y)/6

x = (11 + 2y)/6

We would substitute x = (11 + 2y)/6 into (9^3x)/(9^y). It becomes

[9^3(11 + 2y)/6 ] / (9^y)

= [9^(11 + 2y)/2 ] / (9^y)

= [9^(5.5 + y)/] / (9^y)

We would apply the law of indices

a^b/a^c = a^(b - c)

Therefore

[9^(5.5 + y)/] / (9^y) = 9^(5.5 + y - y)

= 9^(5.5)

= 3^2(5.5)

= 3^11