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A bag contains 5 red marbles, 7 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?

2 Answers

2 votes

Answer:

8/20 or 4 percent

Explanation:

User BioGeek
by
5.5k points
5 votes

Answer:

4.9%

Explanation:

There are a total of 20 marbles.

The probability that the first marble is green is 8/20.

The probability that the second marble is green is 7/19.

The probability that the third marble is green is 6/18.

The total probability is:

P = (8/20) (7/19) (6/18)

P ≈ 0.049

The probability is 4.9%.

User Kevin Hendricks
by
5.0k points
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