Question

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0? x = –6 or x = StartFraction 1 Over 4 EndFraction x = –4 or x = StartFraction 1 Over 6 EndFraction x = StartFraction negative 1 Over 4 EndFraction or x = 6 x = StartFraction negative 1 Over 6 EndFraction or x = 4

Answer 1

the answer is B Good LUCK :)

Explanation:

Answer 2

`g(x)=0` when
`x=-4` and
`x=(1)/(6)`

Explanation:

When
`g(x)=0`

`6x^2+23x-4=0`

This is a quadratic equation and we solve it using the quadratic formula which says for
`ax^2+bx+c=0`

`x=(-b\pm√(b^2-4ac) )/(2a)`

in our case

`a=6\\b=23\\c=-4`

so we put those in and get:

`x=(-23\pm√(23^2-4(6)(-4)) )/(2(6))=(-23\pm25)/(12)`

`\boxed{x=-4}\\\boxed{ x=1/6}`