Question

what is the point of intersection when the system of equations below is graphed on the coordinate plane -x+y=4 6x+y=-3​

Answer 1

Its the 2nd one (-1,3)

Step-by-step explanation:

I took the test review on edge and got that one right

Answer 2

POINTS OF INTERSECTION ARE:

x = -1

y = 3

coordinates : (-1,3)

Coordinates :

Step-by-step explanation:

Condition for intersecting lines

`(a_(1))/(a_(2))\\eq(b_(1))/(b_(2))`

here

a1 ,a2 = coefficients of x (a1 = -1 , a2 = 6)

b1 ,b2 = coefficients of y(b1 = 1 , b2 = 1)

`frac{-1}{6}\\eq(1)/(1)\\eq(1)/(1)`

Calculation :

Here substitution method is used : Value of y from eq (1) is substitued in equation (2)

-x + y = 4

y = 4 + x.............(i)

put value of x in equation (2)

6x + y = -3

6x + 4 + x = -3 ( from i)

7x = -3 - 4

7x = -7

x =
`frac{-7}{7}`

x = -1

using equation(i)

y = 4 + (-1)

y = 4 - 1

y = 3

Check:

The values of x and y should satisfy equation (1) and (2)

for equation 1

-x+y =4

= -(-1) + 3

= 1 + 3

= 4

Hence coordinates satisfy equation 1