Question

Formula

13.
Find the number of real number solutions for the equation.
y2 + 26 = 0
odratic
100%
0
ant and
0
scriminant
g Data
90%
0
ssions and

Answer 1

Explanation:

y²+26=0

disc=0-4*26=-104<0

no real solution.

Answer 2

There are no real solutions.

Explanation:

The equation given is:

`y^(2)+26=0`

`y^(2)=-26`

LHS of the equation is always a positive quantity as square of any number is always positive.But RHS is a negative number.This is not possible.

Hence there are no real solutions.