Question

How many moles of hydrogen gas will be produced if 5.00 moles of zinc reactions with an excess amount of sulfuric acid

Answer 1

Moles of Hydrogen produced is 5 moles

Step-by-step explanation:

The balanced Chemical equation for reaction between zinc and sulfuric acid is :

`Zn(s) + H_(2)SO_(4)(aq) \rightarrow ZnSO_(4)(aq) + H_(2)(g)`

This equation tells that ; when 1 mole of Zn react with 1 mole of sulfuric acid, it produces 1 mole of zinc sulfate and 1 mole of hydrogen.

Since sulfuric acid is in excess so Zinc is the limiting reagent

(Limiting reagent : Substance which get consumed when the reaction completes, limiting reagent helps in predicting the amount of products formed)

Limiting reagent (Zn) will decide the amount of Hydrogen produced

`Zn(s) + H_(2)SO_(4)(aq) \rightarrow ZnSO_(4)(aq) + H_(2)(g)`

`1\ mole\ zinc\rightarrow 1\ mole\ H_(2)`

So,

`5\ mole\ zinc\rightarrow 5\ mole\ H_(2)`

Hence moles of Hydrogen produced is 5 moles