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layla painted walls of a rectangular room. Two walls are 9. Feet by 12 feet the other 2 walls are 9 feet by 20 feet what is the total area of the wall layla painted

User Fseee
by
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1 Answer

2 votes

Answer:

576 sq. feet.

Explanation:

There are two walls of 9 feet by 12 feet dimensions.

Therefore, the total area of those two walls is 2(9 × 12) = 216 sq. ft.

Again, there are two walls of dimensions 9 ft by 20 ft.

So, the total area of those two walls is 2(9 × 20) = 360 sq. feet.

Hence, the total area of the wall that Layla painted is (216 + 360) = 576 sq. feet. (Answer)

User PiQuer
by
5.9k points
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