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Last math question.

What is the equation, in slope-intercept form, of the line parallel to ​y=5x+2 that passes through the point with coordinates (−2,1)?

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Answer:

y = 5x + 11

Explanation:


\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-(1)/(m_1)\\\\k\ ||\ l\iff m_1=m_2\\=========================


\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=5.\\\\\text{Put the value of the slope and the coordinates of the given point (-2, 1)}\\\text{to the equation of a line:}\\\\1=5(-2)+b\\1=-10+b\qquad\text{add 10 to both sides}\\1+10=-10+10+b\\11=b\to b=11\\\\\text{Finally:}\\\\y=5x+11

User Sudhakar B
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