Question

A proton and an electron are located 12 nm apart. Calculate the force of attraction between them?

Answer 1

The force between them is, F = 8.33 x 10⁻¹¹ N

Step-by-step explanation:

Given data,

The distance between the proton and electron, x = 12 nm

= 12 x 10⁻⁹ m

The electrostatic force between them is given by the formula,

`F=k(q_(1)q_(2) )/(x^(2) )`

Where k = 9 x 10⁹ Nm²C⁻²

Substituting the given values,

`F=9*10^(9) (1* 1 )/((12 * 10^(9)) ^(2) )`

F = 8.33 x 10⁻¹¹ N

Hence, the force between them is, F = 8.33 x 10⁻¹¹ N