Question

What color of light is being emitted when the electron drops from n= 6 to n=2

Answer 1

When electron drops from n=6 to n=2, it emits wavelength of 410 nm which gives violet color.

Step-by-step explanation:

Using Rydberg's Equation:

`(1)/(\lambda ) = R\left ( (1)/(n_(f)^(2))-(1)/(n_(i)^(2)) \right )`

Here

R= Rydberg's constant =
`1.097* 10^(7)\ m^(-1)`

`{\lambda }` = Wavelength of photon emitted

`{n_(f)}` = 2

`{n_(i)` = 6

Put the values in the formula:

`(1)/(\lambda ) = 1.097* 10^(7)\left ( (1)/(2^(2))-(1)/(6^(2)) \right )`

`(1)/(\lambda ) = 1.097* 10^(7)* 0.22`

`(1)/(\lambda ) = 2.437* 10^(6) \ m^(-1)`

`\lambda = (1)/(2.478* 10^(6))`

`\lambda = 4.10* 10^(-7)` m

`\lambda` = 410 nm

(1 m =
`10^(-9)`)

This wavelength( 410 nm) is emitted by VIOLET color