Question:
The diameter of the larger circle is 12.5 cm. The diameter of the smaller circle is 3.5 cm.
What is the best approximation for the area of the shaded region?
Use 3.14 to approximate pi.
Small circle inside big circle, shaded region outside smaller circle and inside larger circle.
Answer:
The area of the shaded region is 65.94
![cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s2nakjh21x239bgor6au7ofhpcywd28thn.png)
Explanation:
Given:
Diameter of the small circle = 8.5 cm
Diameter of the Large circle = 12.5 cm
To Find:
The area of the shaded region(refer the below diagram)
Solution:
Step 1 : Finding the area of the small circle
Area of the circle =
![\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69e2ijkvwardlu2n5rrgtkpqc3b44mcw34.png)
where
r is the radius
we have only diameter
so radius =
![(diameter)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/711qyx0eba3lc0bau4xfghh7xqu3fssnh3.png)
=>
![(8.5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gxwuw4hao6z47jt5977ohzqvfe3bvv1qqw.png)
=>4.25
Now
Area of small circle
=>
![\pi * (4.25)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b0ydv5qmb26symbwgr5jffq5zk4921xzjn.png)
=>
![\pi * (4.25) * (4.25)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h0h7pnx6eig95nux9i7xvty5fymyspgd49.png)
=>
![\pi * 18.06](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5oe3e6zorad1il0uxzd5hfh84zk5vdh5f6.png)
=>56.71
![cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s2nakjh21x239bgor6au7ofhpcywd28thn.png)
Step 2 : Finding the area of the large circle
Radius =
![(diameter)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/711qyx0eba3lc0bau4xfghh7xqu3fssnh3.png)
=>
![(12.5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/doi34sejsyeyvydq8irlh9lhkkp9t760ti.png)
=>6.25
Area of large circle
=>
![\pi * (6.25)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/phxkxcscjoog4p7chmmxwdi1fgkw958c09.png)
=>
![\pi * (6.25) * (6.25)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lclipl38vvszo4p4lf3q8fy65osb67grz6.png)
=>
![\pi * 39.06](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t6klrd20ctzvinrb072npyew783trafj1s.png)
=>122.65
![cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s2nakjh21x239bgor6au7ofhpcywd28thn.png)
Step 3 : Finding the area of the shaded region
The area of the shaded region = Area of large circle - Area of small circle
The area of the shaded region = 122.65 - 56.71
The area of the shaded region = 65.94
![cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s2nakjh21x239bgor6au7ofhpcywd28thn.png)