Option C
When
is subtracted from
then the result is
![x^2 + 12x - 9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iy6v6daejx3b00b3couebchaymh7cmz8qv.png)
Solution:
Given that
is subtracted from
![5x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3jb87dmki0drzqm8b3izya232p9qlx6u2q.png)
We have to find the result
Subtraction is a mathematical operation that tells us the difference between two numbers.
When "a" is subtracted from "b", we write in mathematical expression as "b - a"
So
is subtracted from
is written mathematically as:
![\rightarrow 5x^2 - (2x - 3)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6z2jw2yzfd46btzqzt0i869u9cmelnwnai.png)
Expanding the above expression using algebraic identity:
![(a-b)^2 = a^2 - 2ab + b^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f093jriz5g4bw1ruf5wsyuk5wsbkdbzdm8.png)
![\rightarrow 5x^2 - ((2x)^2 -2(2x)(3) + (3)^2)\\\\\rightarrow 5x^2 - (4x^2 - 12x + 9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3u6lb9f1x8q4o8av4096cc372z5bv1j9ng.png)
Multiplying the nnegative sign with terms inside bracket
There are two simple rules to remember:
- When you multiply a negative number by a positive number then the product is always negative.
- When you multiply two negative numbers or two positive numbers then the product is always positive.
![\rightarrow 5x^2 - (4x^2 - 12x + 9)\\\\\rightarrow 5x^2 - 4x^2 + 12x -9\\\\\rightarrow x^2 + 12x - 9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8y6ys8bg1v4yvg481zb4tf73yyilwbpjr0.png)
Hence the result is:
![x^2 + 12x - 9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iy6v6daejx3b00b3couebchaymh7cmz8qv.png)