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What is the missing constant term in the perfect square that starts with X^2 - 8x

User Janella
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2 Answers

2 votes

Answer:

Look at the picture

Explanation:

What is the missing constant term in the perfect square that starts with X^2 - 8x-example-1
User Vangi
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8.2k points
4 votes

Answer:

16

Explanation:

Perfect square in the quadratic from ax² + bx + c

You know an equation is perfect when:

2√(ax²)√(c) = bx

Substitute x² for ax² and 8x for bx. Then isolate c by doing the reverse operations.

2√(ax²)√(c) = bx

2√(x²)√(c) = 8x

2x√c = 8x Divide both sides by 2x

√c = 4 Square both sides to isolate c.

c = 16

The missing constant term is 16.

Check answer:

x² - 8x + 16

(x - 4)²

= (x - 4)(x - 4)

= x² - 4x - 4x + 16

= x² - 8x + 16

User ClicheName
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