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Given p(x)=−3(x−4)2+14, what is the value of p(2)?

Given p(x)=−3(x−4)2+14, what is the value of p(2)?-example-1
User Hyunjoo
by
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2 Answers

21 votes
21 votes

Answer:

p(2) = 2

Explanation:

substitute x = 2 into p(x)

p(2) = - 3(2 - 4)² + 14

= - 3(- 2)² + 14

= - 3(4) + 14

= - 12 + 14

= 2

User Grom
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3.1k points
23 votes
23 votes

PS you cant leave out exponents when typing questions without the attached photo. multiplying by 2 is not the dame as a exponent of 2. Use ^2 to show that a number is to the power of 2.

the value of p(2) in this equation is 2.

User Happy Patel
by
2.7k points
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