Answer:
Therefore, 448 inches² Wrapping paper is needed to wrap a present.
Explanation:
The Present Shape as per dimensions it is CUBOID
Given:
Length = 8 inches
Width = 8 inches
Height = 10 inches
To Find:
Surface Area of Cuboid = ?
( Wrapping paper is needed to wrap a present )
Solution:
By Formula we have
![\textrm{Surface Area of Cuboid}= 2(Length* Width +Width* Height + Height* Length)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kjl1wiovmxc6ar3vt2hmv4alfpmtuqwqro.png)
Substituting the given value in above formula we will get
![\textrm{Surface Area of Cuboid}= 2(8* 8 + 8* 10 + 10* 8)\\\\\textrm{Surface Area of Cuboid}= 2(224)\\\\\textrm{Surface Area of Cuboid}= 448\ inches^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjxg8kz6dm8gbj0bzsiwa5soit9jdo24oz.png)
Therefore, 448 inches² Wrapping paper is needed to wrap a present .