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A 1.8 × 10^3 kg car is parked on a hill on a 15° incline. A 1.25 × 10^4 N frictional force holds the car in place. What's the coefficient of static friction
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A 1.8 × 10^3 kg car is parked on a hill on a 15° incline. A 1.25 × 10^4 N frictional force holds the car in place. What's the coefficient of static friction

User Ben Hoffstein
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6 votes

Answer:

The coefficient of static friction = 0.73

Step-by-step explanation:

In order to solve this problem we must make a free body diagram of the car on the inclined surface and the forces acting on it. We must bear in mind that there is no movement and therefore all the forces summations on the y axis should be equal to zero.

The friction force is equal to the product of the normal force multiplied by the coefficient of friction.

There is an attached image with the forces acting and the equations deducted.

A 1.8 × 10^3 kg car is parked on a hill on a 15° incline. A 1.25 × 10^4 N frictional-example-1
User Vasanth Nag K V
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