Question

If a gas is cooled from 323.0 K to 273.15 K and volume is kept constant, what final

pressure would result if the original pressure was 0.986 atm?

Answer 1

634 mmHg
Step-by-step explanation:
From the Ideal Gas Laws we know that
(
P
V
T
)
1
=
(
P
V
T
)
2
Inserting our given values into this equation with the correct temperature values we get:
750
m
m
H
g
⋅
V
1
323
’
K
=
P
2
⋅
V
2
273.15
’
K
;
V
1
=
V
2
P
2
=
750
⋅
(
273.15
323
)
P
2
=
634
m
m
H
g